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Simplifying 2b2 + -4b + -24 = 0 Reorder the terms: -24 + -4b + 2b2 = 0 Solving -24 + -4b + 2b2 = 0 Solving for variable 'b'. Factor out the Greatest Common Factor (GCF), '2'. 2(-12 + -2b + b2) = 0 Ignore the factor 2.Subproblem 1
Set the factor '(-12 + -2b + b2)' equal to zero and attempt to solve: Simplifying -12 + -2b + b2 = 0 Solving -12 + -2b + b2 = 0 Begin completing the square. Move the constant term to the right: Add '12' to each side of the equation. -12 + -2b + 12 + b2 = 0 + 12 Reorder the terms: -12 + 12 + -2b + b2 = 0 + 12 Combine like terms: -12 + 12 = 0 0 + -2b + b2 = 0 + 12 -2b + b2 = 0 + 12 Combine like terms: 0 + 12 = 12 -2b + b2 = 12 The b term is -2b. Take half its coefficient (-1). Square it (1) and add it to both sides. Add '1' to each side of the equation. -2b + 1 + b2 = 12 + 1 Reorder the terms: 1 + -2b + b2 = 12 + 1 Combine like terms: 12 + 1 = 13 1 + -2b + b2 = 13 Factor a perfect square on the left side: (b + -1)(b + -1) = 13 Calculate the square root of the right side: 3.605551275 Break this problem into two subproblems by setting (b + -1) equal to 3.605551275 and -3.605551275.Subproblem 1
b + -1 = 3.605551275 Simplifying b + -1 = 3.605551275 Reorder the terms: -1 + b = 3.605551275 Solving -1 + b = 3.605551275 Solving for variable 'b'. Move all terms containing b to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + b = 3.605551275 + 1 Combine like terms: -1 + 1 = 0 0 + b = 3.605551275 + 1 b = 3.605551275 + 1 Combine like terms: 3.605551275 + 1 = 4.605551275 b = 4.605551275 Simplifying b = 4.605551275Subproblem 2
b + -1 = -3.605551275 Simplifying b + -1 = -3.605551275 Reorder the terms: -1 + b = -3.605551275 Solving -1 + b = -3.605551275 Solving for variable 'b'. Move all terms containing b to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + b = -3.605551275 + 1 Combine like terms: -1 + 1 = 0 0 + b = -3.605551275 + 1 b = -3.605551275 + 1 Combine like terms: -3.605551275 + 1 = -2.605551275 b = -2.605551275 Simplifying b = -2.605551275Solution
The solution to the problem is based on the solutions from the subproblems. b = {4.605551275, -2.605551275}Solution
b = {4.605551275, -2.605551275}
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